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 A010136 Continued fraction for sqrt(46). 3
 6, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2, 6, 2, 1, 1, 3, 1, 12, 1, 3, 1, 1, 2 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 LINKS Harry J. Smith, Table of n, a(n) for n = 0..20000 A. J. van der Poorten, An introduction to continued fractions, Unpublished. A. J. van der Poorten, An introduction to continued fractions, Unpublished [Cached copy] G. Xiao, Contfrac Index entries for linear recurrences with constant coefficients, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1). FORMULA a(n) = (1/396)*(-346*(n mod 12)+83*((n+1) mod 12)-49*((n+2) mod 12)+17*((n+3) mod 12)+50*((n+4) mod 12)+149*((n+5) mod 12)-115*((n+6) mod 12)-16*((n+7) mod 12]) +17*((n+8) mod 12)+83*((n+9) mod 12)-49*((n+10) mod 12)+380*((n+11) mod 12))-6*(C(2*n,n) mod 2). - Paolo P. Lava, Jul 23 2009 EXAMPLE 6.782329983125268139064556326... = 6 + 1/(1 + 1/(3 + 1/(1 + 1/(1 + ...)))). - Harry J. Smith, Jun 06 2009 MATHEMATICA ContinuedFraction[Sqrt[46], 300] (* Vladimir Joseph Stephan Orlovsky, Mar 07 2011 *) PROG (PARI) { allocatemem(932245000); default(realprecision, 16000); x=contfrac(sqrt(46)); for (n=0, 20000, write("b010136.txt", n, " ", x[n+1])); } \\ Harry J. Smith, Jun 06 2009 CROSSREFS Cf. A010500 (decimal expansion). - Harry J. Smith, Jun 06 2009] Cf. A190567. [Bruno Berselli, Nov 21 2011] Sequence in context: A021624 A021066 A082730 * A087256 A154911 A152935 Adjacent sequences:  A010133 A010134 A010135 * A010137 A010138 A010139 KEYWORD nonn,cofr,easy AUTHOR STATUS approved

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Last modified July 23 00:43 EDT 2019. Contains 325228 sequences. (Running on oeis4.)