%I #11 Jul 19 2013 05:02:43
%S 1,2,5,14,45,186,945,5778,44037,403470,4344877,56072378,793804721,
%T 12734185106,229632768005,4628786367502,105803768420397,
%U 2626282179198138,71539181027191729,2076395667668755090,65704452165048754181
%N A007824(n)/16.
%C Previous name was: For N=Sum a(i).2^i, where the a(i) are binary, define a "derivative" D(N)/D(2)=Sum i.a(i).2^(i-1); sequence gives n-th derivative of 16 (divided by 16) (cf A007824).
%F a(n) = A007824(n)/16. - _Michel Marcus_, Jul 18 2013
%K nonn
%O 0,2
%A Ralph Buchholz [ ralph(AT)defcen.gov.au ], Leisa Condie
%E Edited by _Michel Marcus_, Jul 18 2013