1,4
Let b(n)=2*(3/2)^n-1. Then a(n)=-b(1-n)*3^(n-1) for n>0. A083313(n)=A064686(n)=b(n)*2^(n-1) for n>0. - Michael Somos Aug 06 2006
Sequence in context: A008780 A101992 A160671 * A124857 A126398 A159486
Adjacent sequences: A003060 A003061 A003062 * A003064 A003065 A003066
sign
Henrik Johansson (Henrik.Johansson(AT)Nexus.SE)