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A002217 Starting with n, repeatedly calculate the sum of prime factors (with repetition) of the previous term, until reaching 0 or a fixed point: a(n) is the number of terms in the resulting sequence.
(Formerly M0150 N0060)
9
2, 1, 1, 1, 1, 2, 1, 3, 3, 2, 1, 2, 1, 4, 4, 4, 1, 4, 1, 4, 3, 2, 1, 4, 3, 5, 4, 2, 1, 3, 1, 3, 5, 2, 3, 3, 1, 4, 5, 2, 1, 3, 1, 5, 2, 4, 1, 2, 5, 3, 5, 2, 1, 2, 5, 2, 3, 2, 1, 3, 1, 6, 2, 3, 5, 5, 1, 4, 6, 5, 1, 3, 1, 6, 2, 2, 5, 5, 1, 2, 3, 2, 1, 5, 3, 3, 4, 2, 1, 2, 5, 5, 3, 6, 5, 2, 1, 5, 2, 5, 1, 3, 1, 2, 5 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
REFERENCES
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
LINKS
T. D. Noe and Christian N. K. Anderson, Table of n, a(n) for n = 1..10000 (first 1000 terms are from T. D. Noe)
Christian N. K. Anderson, n, the fixed point, a(n), and the trajectories for n = 1..10000.
M. Lal, Iterates of a number-theoretic function, Math. Comp., 23 (1969), 181-183.
Eric Weisstein's World of Mathematics, Sum of Prime Factors
EXAMPLE
20 -> 2+2+5 = 9 -> 3+3 = 6 -> 2+3 = 5, so a(20) = length of sequence {20,9,6,5} = 4.
MATHEMATICA
sopfr[n_] := Times @@@ FactorInteger[n] // Total;
a[1] = 2; a[n_] := Length[ FixedPointList[sopfr, n]] - 1;
Array[a, 105] (* Jean-François Alcover, Feb 09 2018 *)
CROSSREFS
Cf. A001414 (sum of prime factors of n), A029908 (fixed point that is reached).
Sequence in context: A029434 A358192 A156281 * A344173 A157047 A059342
KEYWORD
nonn
AUTHOR
EXTENSIONS
More terms and better description from Reinhard Zumkeller, Apr 08 2003
Incorrect comment removed by Harvey P. Dale, Aug 16 2011
STATUS
approved

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Last modified April 23 23:26 EDT 2024. Contains 371917 sequences. (Running on oeis4.)