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A000478
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Number of ways of placing n labeled balls into 3 indistinguishable boxes with at least 2 balls in each box.
(Formerly M4978 N2138)
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9
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15, 105, 490, 1918, 6825, 22935, 74316, 235092, 731731, 2252341, 6879678, 20900922, 63259533, 190957923, 575363776, 1731333808, 5205011031, 15638101281, 46962537810, 140988276150, 423174543025, 1269959836015, 3810785476980, 11434235478348, 34306598748315, 102927849307725
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OFFSET
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6,1
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COMMENTS
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Associated Stirling numbers.
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REFERENCES
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L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 222.
F. N. David and D. E. Barton, Combinatorial Chance. Hafner, NY, 1962, p. 296.
J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 76.
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
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LINKS
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FORMULA
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E.g.f.: ((exp(x) - 1 - x)^3)/3!.
G.f.: x^6*(12*x^3 - 40*x^2 + 45*x - 15)/((1 - x)^3*(1 - 2*x)^2*(3*x - 1)). - Simon Plouffe in his 1992 dissertation
a(n) = (1+n+n^2)/2 - (1/2 + n/4)*2^n + 3^n/6. - Michael Steyer (m.steyer(AT)osram.de), Jan 09 2005
a(n) = 10*a(n-1) - 40*a(n-2) + 82*a(n-3) - 91*a(n-4) + 52*a(n-5) - 12*a(n-6), n > 11. - Harvey P. Dale based on Michael Steyer's formula, Jul 17 2011
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EXAMPLE
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a(6) = 6!/(2!*2!*2!*3!) = 15.
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MATHEMATICA
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Table[(1+n+n^2)/2-(1/2+n/4)*2^n+3^n/6, {n, 6, 30}] (* or *) LinearRecurrence[ {10, -40, 82, -91, 52, -12}, {15, 105, 490, 1918, 6825, 22935}, 25] (* Harvey P. Dale, Jul 17 2011 *)
offset = 6; terms = 26; egf = (Exp[x]-1-x)^3/3!; Drop[CoefficientList[egf + O[x]^(terms+offset), x]*Range[0, terms+offset-1]!, offset] (* Jean-François Alcover, May 07 2017 *)
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PROG
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(PARI) Vec(x^6*(12*x^3-40*x^2+45*x-15)/((1-x)^3*(1-2*x)^2*(3*x-1))+O(x^66)) /* Joerg Arndt, Apr 10 2013 */
a = 15; n = 7; z = 4; s = 15;
while True:
yield a
z = 2*z; s += n*(z-2) + 3; a = 3*a + s; n += 1
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CROSSREFS
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KEYWORD
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nonn,easy,nice
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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